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CalculatorsFixie Skid Patch Calculator

Fixie Skid Patch Calculator

A fixed gear skids on the same tyre spots unless the chainring and cog spread those spots out. More patches means the tyre lasts longer.

Inputs

Units

Results

Skid patches (one foot)
17
Ambidextrous patches
34

How the number is made

Patches = cog ÷ gcd(chainring, cog). If that count is odd, ambidextrous skidding (both feet forward) doubles it. An even count stays the same because both feet hit the same patches.

Prime cogs against a non-multiple chainring maximise patches. This does not make a bad gear ratio a good one.

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Questions

Why do prime cogs help?

A prime cog shares a divisor only when the chainring is a multiple of that prime. Otherwise gcd is 1 and you get one patch per cog tooth. A 51 T ring with a 17 T cog does not.

Is 48×17 enough patches?

gcd(48, 17) is 1, so 17 one-foot patches and 34 ambidextrous. That is a friendly combination.

Does a prime cog always give one patch per tooth?

No. A prime cog shares a divisor only when the chainring is a multiple of that prime. 51 by 17 still has one patch, not seventeen.

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